How to return multiple values from *args?

Question

I have a hello function and it takes n arguments (see below code).

def hello(*args):
  # return values

I want to return multiple values from *args. How to do it? For example:

d, e, f = hello(a, b, c)

SOLUTION:

def hello(*args):
  values = {} # values
  rst = [] # result
  for arg in args:
    rst.append(values[arg])
  return rst

a, b, c = hello('d', 'e', f)
a, b = hello('d', 'f')

Just return list. :) :D

No sure what you mean. `return args` will return multiple values from `*args`. — Marcelo Cantos, Dec 05 '11 at 06:34
Duplicate , answered in detail here. [Stack overflow ret mul val python][1] [1]: http://stackoverflow.com/questions/354883/how-do-you-return-multiple-values-in-python — Ray Garner, Dec 05 '11 at 06:35
In hello function I'm assigning values to variables. I get that variables from *args. You know args are dynamic. So I don't know return multiple values from dynamic variables /args/ like example. — Zeck, Dec 05 '11 at 06:40

Johan Boulé · Accepted Answer · 2011-12-05T07:21:12.947

So, you want to return a new tuple with the same length as args (i.e. len(args)), and whose values are computed from args[0], args[1], etc. Note that you can't modify 'args' directly, e.g. you can't assign args[0] = xxx, that's illegal and will raise a TypeError: 'tuple' object does not support item assignment. What You need to do then is return a new tuple whose length is the same as len(args). For example, if you want your function to add one to every argument, you can do it like this:

def plus_one(*args):
    return tuple(arg + 1 for arg in args)

Or in a more verbose way:

def plus_one(*args):
    result = []
    for arg in args: result.append(arg + 1)
    return tuple(result)

Then, doing :

d, e, f = plus_one(1, 2, 3)

will return a 3-element tuple whose values are 2, 3 and 4.

The function works with any number of arguments.

You know 'args' arguments are dynamic. How to return multiple values from dynamic 'args'? Sorry for poor english. Please see my comment. — Zeck, Dec 05 '11 at 06:46
Woow. Better solution than me. Thank you for sharing your knowledge. :) — Zeck, Dec 05 '11 at 08:42

score 1 · Answer 2 · answered Dec 05 '11 at 06:34

1

Just return a tuple:

def hello(*args):
    return 1, 2, 3

...or...

    return (1, 2, 3)

answered Dec 05 '11 at 06:34

detly

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score 1 · Answer 3 · answered Dec 05 '11 at 06:42

args is a list. if you return a sequence (list, tuple), Python will try to iterate and assign to your d, e, f variables. so following code is ok.

def hello(*args):
   return args

d, e,  f = hello(1,2,3)

As long as you have, the right number of values in the *args list. It will be assigned to your variables. If not, il will raise a ValueError exception.

d, e, f = hello(1, 2) #raise ValueError

I hope ith helps

score 0 · Answer 4 · answered Dec 05 '11 at 06:34

Just return them. For instance, if you want to return the parameters unmodified, do this:

def hello(*args):
    return args

If you want to return something else, return that instead:

def hello(*args):
    # ...
    # Compute d, e and f
    # ...
    return d, e, f

How to return multiple values from *args?

4 Answers4

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