Could work like this:
DELETE FROM tbl
WHERE  EXISTS (
   SELECT *
   FROM   tbl t
   WHERE (t.lang_original,   t.lang_target,   t.word)
       = (tbl.lang_original, tbl.lang_target, tbl.word)
   AND tbl.id_word > t.id_word
   )
If @Jason is right, and MySQL does not allow to reference the delete table, here is another form that works independently:
DELETE FROM tbl
USING (
   SELECT min(id_word) AS min_id, lang_original, lang_target, word
   FROM   tbl t
   GROUP  BY lang_original, lang_target, word
   HAVING count(*) > 1
   ) x
WHERE (tbl.lang_original, tbl.lang_target, tbl.word)
   =  (  x.lang_original,   x.lang_target,   x.word)
AND    tbl.id_word > x.min_id
Both variants leave the duplicate with the smallest id alive and kill the rest.
If you want to save all your translations to the word with the smallest id in a group of dupes first:
UPDATE tbl SET translation = all_trans
FROM  (
   SELECT min(id_word) AS min_id, group_concat(translation) AS all_trans
   FROM   tbl
   GROUP  BY lang_original, lang_target, word
   HAVING count(*) > 1
   ) t
WHERE  tbl.id_word = t.min_id