shell script - how to split a string with delimiter ","

Question

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Split string based on delimiter in bash?

i have a shell script which call by php and pass a variable ($1)

When i using MYVAR = $1, and echo MYVAR is not working

how can i assign this variable ($1) to another variable and split it with delimiter "," and convert it into a array for looping?

it cant solve my problem "When i using MYVAR = $1, and echo MYVAR is not working" — user192344, Dec 19 '11 at 02:14
Is that the literal notation in your script? Wouldn't that give you an error message? — mario, Dec 19 '11 at 02:16

score 4 · Accepted Answer · answered Dec 19 '11 at 02:19

Well, guessed answer in absence of code.

Variable assignments in shell scripts must be:

  MYVAR=$1

Spaces around are incorrect:

  MYVAR = $1

And the echo must output an actual variable, using the $ prefix:

  echo $MYVAR

Not just the literal string:

  echo NOVAR

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