Weird javascript output

Question

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Workarounds for JavaScript parseInt octal bug

I was learning the parseInt() function of javascript and was just trying out, and out of nowhere

parseInt('08')  returns 0

moreover,

parseInt('07')  returns 7 //which is correct

but again

parseInt('09')   returns 0 // really, are you kidding me.?

Either I am crazy or I am missing something?

You last example (with '9') is a typo - you get the surprising result from '09', not '9'. — Pointy, Dec 19 '11 at 19:14
Related: http://stackoverflow.com/questions/1545164/how-to-parseint-a-string-with-leading-0 — Rob Hruska, Dec 19 '11 at 19:15
Related: http://stackoverflow.com/questions/7318385/problems-with-javascript-parseint — Rob Hruska, Dec 19 '11 at 19:15
parseInt('9') returns 9 for me. But '08' returns 0 as you said. Totally weird. Never seen this before. FF latest. — techfoobar, Dec 19 '11 at 19:15
Related: http://stackoverflow.com/search?q=javascript+parseint — Rob Hruska, Dec 19 '11 at 19:15

score 3 · Answer 1 · answered Dec 19 '11 at 19:14

3

Its because its doing octal when the string starts with 0.

You should pass the radix of 10 as the second parameter.

answered Dec 19 '11 at 19:14

Daniel A. White

slolife · Accepted Answer · 2011-12-19T20:01:40.813

2

You need to specify the radix:

parseInt('08', 10);  // base 10 radix

Running your javascript thru JSLint will call this out as well.

From the documentation, parseInt parses the string as octal when the string starts with a 0, if no radix is specified.

edited Dec 19 '11 at 20:01

answered Dec 19 '11 at 19:15

slolife

score 0 · Answer 3 · answered Dec 19 '11 at 19:15

0

No, you're. Only parseInt obeys rules for octal numbers and applies them when the string begins with 0.

answered Dec 19 '11 at 19:15

3 Answers3