I have a class that need to make some magic with every operator, like __add__, __sub__ and so on.
Instead of creating each function in the class, I have a metaclass which defines every operator in the operator module.
import operator
class MetaFuncBuilder(type):
    def __init__(self, *args, **kw):
        super().__init__(*args, **kw)
        attr = '__{0}{1}__'
        for op in (x for x in dir(operator) if not x.startswith('__')):
            oper = getattr(operator, op)
            # ... I have my magic replacement functions here
            # `func` for `__operators__` and `__ioperators__`
            # and `rfunc` for `__roperators__`
            setattr(self, attr.format('', op), func)
            setattr(self, attr.format('r', op), rfunc)
The approach works fine, but I think It would be better if I generate the replacement operator only when needed.
Lookup of operators should be on the metaclass because x + 1 is done as type(x).__add__(x,1) instead of x.__add__(x,1), but it doesn't get caught by __getattr__ nor __getattribute__ methods.
That doesn't work:
class Meta(type):
     def __getattr__(self, name):
          if name in ['__add__', '__sub__', '__mul__', ...]:
               func = lambda:... #generate magic function
               return func
Also, the resulting "function" must be a method bound to the instance used.
Any ideas on how can I intercept this lookup? I don't know if it's clear what I want to do.
For those questioning why do I need to this kind of thing, check the full code here.
That's a tool to generate functions (just for fun) that could work as replacement for lambdas. 
Example:
>>> f = FuncBuilder()
>>> g = f ** 2
>>> g(10)
100
>>> g
<var [('pow', 2)]>
Just for the record, I don't want to know another way to do the same thing (I won't declare every single operator on the class... that will be boring and the approach I have works pretty fine :). I want to know how to intercept attribute lookup from an operator.