Regex between, from the last to specific end

Question

Today my wish is to take text form the string. This string must be, between last slash and .partX.rar or .rar

First I tried to find edge's end of the word and then the beginning. After I get that two elements I merged them but I got empty results.

String:

http://hosting.xyz/1234/15-game.part4.rar.html

http://hosting.xyz/1234/16-game.rar.html

Regex:

Begin:(([^/]*)$) - start from last /

End:(.*(?=.part[0-9]+.rar|.rar)) stop before .partX.rar or .rar

As you see, if I merge that codes I won't get any result. What is more, "end" select me only .partX instead of .partX.rar

All what I want is: 15-game.part4.rar and 16-game.rar

What i tried:

(([^/]*)$)(.*(?=.part[0-9]+.rar|.rar))

(([^/]*)$)

(.*(?=.part[0-9]+.rar|.rar))

I tried also

/[a-zA-Z0-9]+

but I do not know how select symbols.. This could be the easiest way. But this select only letters and numbers, not - or _. If I could select symbols..

as I said `(([^/]*)$)(.*(?=.part[0-9]+.rar|.rar))` this I tried, I tried also `(([^/]*)$)` and `(.*(?=.part[0-9]+.rar|.rar))`, I tried also `/[a-zA-Z0-9]+` but I do not know how select symbols.. This could be the easiest way. But this select only letters and numbers, not `-` - do you know how to select till `.` dot? — deadfish, Jan 04 '12 at 19:24

Sergio Tulentsev · Answer 1 · 2012-01-04T19:42:20.657

1

Nothing could be simpler! :-)

Use this:

new Regex("^.*\/(.*)\.html$")

You'll find your filename in the first captured group (don't have a c# compiler at hand, so can't give you working sample, but you have a working regex now! :-) )

See a demo here: http://rubular.com/r/UxFNtJenyF

edited Jan 04 '12 at 19:42

answered Jan 04 '12 at 19:22

Sergio Tulentsev

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Ah. C# guy :-) Then put this into a Regex constructor: `^.*\/(.*)$`. Leading and trailing slashes are part of regex literal in some languages. – Sergio Tulentsev Jan 04 '12 at 19:34
Yeah, I see but doesn't on C#, and `.html` is no need. C# gives me all source of link. – deadfish Jan 04 '12 at 19:34

score 1 · Answer 2 · answered Jan 04 '12 at 19:38

You don't really need a regex for this as you can merely split the url on / and then grab the part of the file name that you need. Since you didn't mention a language, here's an implementation in Perl:

use strict;
use warnings;

my $str1="http://hosting.xyz/1234/15-game.part4.rar.html";

my $str2="http://hosting.xyz/1234/16-game.rar.html";

my $file1=(split(/\//,$str1))[-1]; #last element of the resulting array from splitting on slash

my $file2=(split(/\//,$str2))[-1];

foreach($file1,$file2)
{
  s/\.html$//; #for each file name, if it ends in ".html", get rid of that ending.
  print "$_\n";
}

The output is:

15-game.part4.rar
16-game.rar

Yes, sorry forget about code language. I though that regex is universal. Btw. your code helped me a lot. I forgot about rule **KISS**! :) However it is not regex, doh! :P — deadfish, Jan 05 '12 at 14:56

score 0 · Accepted Answer · answered Jan 04 '12 at 20:13

0

I'm not a C# coder so can't write full code here but I think you'll need support of negative lookahead here like this:

new Regex("/(?!.*/)(.+?)\.html$");

Matched Group # 1 will have your string i.e. "16-game.rar" OR "15-game.part4.rar"

answered Jan 04 '12 at 20:13

anubhava

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could I ask you to explain me this regex command, I would appreciate for this. Thanks in advance! – deadfish Jan 05 '12 at 14:59
1

Sure I will try. This regex basically has a negative lookahead `/(?!.*/)` which means match a `/` which is **NOT followed** by some text and another `/`. This basically makes sure that we **match only last /**. Rest is straight forward where `(.+?)\.html` matches a text that has `.html` in the end. – anubhava Jan 05 '12 at 15:05

score 0 · Answer 4 · answered Jan 04 '12 at 20:58

0

Use two regexes:

start to substitute .*/ with nothing;
then substitute \.html with nothing.

Job done!

answered Jan 04 '12 at 20:58

fge

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Regex between, from the last to specific end

4 Answers4

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