After searching for this same functionality, I ended up writing my own PHP script to act as a proxy. The trouble I kept running into is even when you get the RAW version/link from Github and link to it in your own page, the header sent over was 'text/plain' and Chrome was not executing my JavaScript file from Github. I also didn't like the other links posted for using third party services because of the obvious security/tampering issues possible.
So using this script, I can pass over the RAW link from Github, have the script set the correct headers, and then output the file as if it were coming from my own server. This script can also be used with a secure application to pull in non-secure scripts without throwing SSL errors warning of "Non-secure links used".
Linking:
<script src="proxy.php?link=https://raw.githubusercontent.com/UserName/repo/master/my_script.js"></script>
proxy.php
<?php
###################################################################################################################
#
# This script can take two URL variables
#
# "type"
# OPTIONAL
# STRING
# Sets the type of file that is output
#
# "link"
# REQUIRED
# STRING
# The link to grab and output through this proxy script
#
###################################################################################################################
# First we need to set the headers for the output file
# So check to see if the type is specified first and if so, then set according to what is being requested
if(isset($_GET['type']) && $_GET['type'] != ''){
switch($_GET['type']){
case 'css':
header('Content-Type: text/css');
break;
case 'js':
header('Content-Type: text/javascript');
break;
case 'json':
header('Content-Type: application/json');
break;
case 'rss':
header('Content-Type: application/rss+xml; charset=ISO-8859-1');
break;
case 'xml':
header('Content-Type: text/xml');
break;
default:
header('Content-Type: text/plain');
break;
}
# Otherwise, try and determine what file type should be output by the file extension from the link
}else{
# See if we can find a file type in the link specified and set the headers accordingly
# If css file extension is found, then set the headers to css format
if(strstr($_GET['link'], '.css') != FALSE){
header('Content-Type: text/css');
# If javascript file extension is found, then set the headers to javascript format
}elseif(strstr($_GET['link'], '.js') != FALSE){
header('Content-Type: text/javascript');
# If json file extension is found, then set the headers to json format
}elseif(strstr($_GET['link'], '.json') != FALSE){
header('Content-Type: application/json');
# If rss file extension is found, then set the headers to rss format
}elseif(strstr($_GET['link'], '.rss') != FALSE){
header('Content-Type: application/rss+xml; charset=ISO-8859-1');
# If css xml extension is found, then set the headers to xml format
}elseif(strstr($_GET['link'], '.xml') != FALSE){
header('Content-Type: text/xml');
# If we still haven't found a suitable file extension, then just set the headers to plain text format
}else{
header('Content-Type: text/plain');
}
}
# Now get the contents of our page we're wanting
$contents = file_get_contents($_GET['link']);
# And finally, spit everything out
echo $contents;
?>