Regex - match everything without whitespace

Question

I now using in Regex this expressions,

([\x20-\x7E]+) - match everything with space

([\x21-\x7E]+) - match everything without space

But i need more performance and in benchmark i see that (.*) is 2x more faster than ([\x20-\x7E]+). Then i replaced that.

But how to write ([\x21-\x7E]+) in (.*) ? Or in other words how to modify (.*) to match everything without whitespace characters?

Thanks!

anubhava · Accepted Answer · 2021-06-23T17:56:28.787

48

To match everything except whitespace use:

[^\s]+

or

\S+

edited Jun 23 '21 at 17:56

answered Jan 24 '12 at 17:26

anubhava

3

Or just `\S+`. But this is much too easy. This can't be the real answer can it? Svisstack was asking about benchmarking, so I assume this isn't Svisstack's first time using a Regex? – Buh Buh Jan 24 '12 at 17:43
1

@Buh Buh: works little bit slower, i was thinking about performance improvment but this is only 5% slower and i have cleaner code, i forgive this up, this is why i accepted – Svisstack Jan 25 '12 at 00:02
Why not `[^\s.]+`? – e-info128 Jun 23 '21 at 17:50
But why exclude dot? – anubhava Jun 23 '21 at 17:56

score 0 · Answer 2 · answered Dec 03 '22 at 11:12

0

I was forced to make the following

"^((?!\s).)*$"

Or if you want it for multiple symbols

"^((?![\s]).)*$"

It will be work in Notepad++ too

answered Dec 03 '22 at 11:12

Garric

2 Answers2