Strings written to file do not preserve line breaks

Question

I am trying to write a String(lengthy but wrapped), which is from JTextArea. When the string printed to console, formatting is same as it was in Text Area, but when I write them to file using BufferedWriter, it is writing that String in single line.

Following snippet can reproduce it:

public class BufferedWriterTest {
    public static void main(String[] args) throws IOException {
        String string = "This is lengthy string that contains many words. So\nI am wrapping it.";
        System.out.println(string);
        File file = new File("C:/Users/User/Desktop/text.txt");
        FileWriter fileWriter = new FileWriter(file);
        BufferedWriter bufferedWriter = new BufferedWriter(fileWriter);
        bufferedWriter.write(string);
        bufferedWriter.close();
    }
}

What went wrong? How to resolve this? Thanks for any help!

were the size of your console and the size of your JTeaxtArea the same? — MozenRath, Feb 08 '12 at 18:30
if not, then probably its because you need \r\n for windows new line — MozenRath, Feb 08 '12 at 18:31
Eclipse Console and JTextArea is 750x400 px. If I have to add \r\n, how do I do for input from JTextArea? Is it possible to identify line breaks? — Ahamed, Feb 08 '12 at 18:38

Kevin K · Accepted Answer · 2016-04-22T03:56:01.793

Text from a JTextArea will have \n characters for newlines, regardless of the platform it is running on. You will want to replace those characters with the platform-specific newline as you write it to the file (for Windows, this is \r\n, as others have mentioned).

I think the best way to do that is to wrap the text into a BufferedReader, which can be used to iterate over the lines, and then use a PrintWriter to write each line out to a file using the platform-specific newline. There is a shorter solution involving string.replace(...) (see comment by Unbeli), but it is slower and requires more memory.

Here is my solution - now made even simpler thanks to new features in Java 8:

public static void main(String[] args) throws IOException {
    String string = "This is lengthy string that contains many words. So\nI am wrapping it.";
    System.out.println(string);
    File file = new File("C:/Users/User/Desktop/text.txt");

    writeToFile(string, file);
}

private static void writeToFile(String string, File file) throws IOException {
    try (
        BufferedReader reader = new BufferedReader(new StringReader(string));
        PrintWriter writer = new PrintWriter(new FileWriter(file));
    ) {
        reader.lines().forEach(line -> writer.println(line));
    }
}

uhm, stacking all these readers to do simple replacement? `string.replace("\\n", System.getProperty("line.separator"));` — unbeli, Feb 08 '12 at 19:06
@unbeli, Replacement is quick if the String is short, for very lengthier strings, the above approach holds good. I have tested it though. — Ahamed, Feb 08 '12 at 20:30
@unbeli - `String.replace()` requires creating a new object, which temporarily doubles the memory requirement, so it's not ideal for large amounts of data. Though granted, with the data coming from a `JTextArea`, I can't imagine the string would be terribly large, so it would probably work just as well for the most part — Kevin K, Feb 08 '12 at 20:46

score 7 · Answer 2 · edited May 23 '17 at 10:31

7

Please see the following question on how to appropriately handle newlines.

How do I get a platform-dependent new line character?

Basically you want to use

String newLineChar = System.getProperty("line.separator");

and then use the newLineChar instead of "\n"

edited May 23 '17 at 10:31

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answered Feb 08 '12 at 18:39

jluzwick

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score 3 · Answer 3 · answered Feb 08 '12 at 18:35

3

I just ran your program, and adding a carriage return (\r) before your newline (\n) did the trick for me.

If you want to get a system independent line separator, one can be found in the system propery line.separator

String separator = System.getProperty("line.separator");
String string = "This is lengthy string that contains many words. So" + separator
            + "I am wrapping it.";

answered Feb 08 '12 at 18:35

nicholas.hauschild

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I am getting String from JTextArea, do I have to manually identify the line breaks and insert `line.separator`? Is that the only way? :( – Ahamed Feb 08 '12 at 18:50
There may be better ways that than, but it sounds like that solution would work for you. – nicholas.hauschild Feb 08 '12 at 19:03

score 1 · Answer 4 · answered Jun 26 '18 at 13:48

If you wish to keep the carriage return characters from a Java string into a file. Just replace each break line character (which is recognized in java as: \n) as per the following statement:

TempHtml = TempHtml.replaceAll("\n", "\r\n");

Here is an code example,

        // When Execute button is pressed
        String TempHtml = textArea.getText();
        TempHtml = TempHtml.replaceAll("\n", "\r\n");
        try (PrintStream out = new PrintStream(new FileOutputStream("C:/Temp/temp.html"))) {
            out.print(TempHtml);
        } catch (FileNotFoundException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        System.out.println(TempHtml);

score 0 · Answer 5 · edited May 23 '17 at 12:03

0

If you are using a BufferedWriter, you could also use the .newline() method to re-add the newline based on your platform.

See this related question: Strings written to file do not preserve line breaks

edited May 23 '17 at 12:03

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answered Feb 09 '16 at 11:40

Christian Vielma

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Strings written to file do not preserve line breaks

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