What does "void ()(void *)" mean in C++?

Asked Feb 21 '12 at 02:07

Active Jan 01 '16 at 21:50

Viewed 8,559 times

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It's the parameter in pthread_create(). I think each part means:

void *: The return value is a void pointer.
(*): It's a pointer to a function.
(void *): It takes an untyped pointer as a parameter.

Is that correct?

edited Jan 01 '16 at 21:50

Peter Mortensen

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asked Feb 21 '12 at 02:07

Marty

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Just check it yourself on cdecl.org. – Karl Knechtel Feb 21 '12 at 03:48

1 Answers1

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Yes, it is the signature of a nameless function pointer that takes and returns void *.

If it had a name (as in a variable) it would be:

void *(*myFuncName)(void*)

edited Apr 07 '13 at 13:05

Constantino Tsarouhas

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answered Feb 21 '12 at 02:09

Michael Chinen

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For which compilers is this syntax legal? The R package igraph does not compile on the CRAN Solaris server due to a "syntax error" around the use of "void (*)(void)": https://www.r-project.org/nosvn/R.check/r-patched-solaris-x86/igraph-00install.html – landau Jul 20 '17 at 15:58