Deriving (Expanding) a Control Template in WPF

Question

I have this DataGrid I want to change the Disabled behaviour (xaml); I want to change this small part in the template.

If it is not possible i dont mind to use:

<Setter Property="OverridesDefaultStyle" Value="True"/>

And To replace the entire xaml (template) of my control, But I need the complete template to copy paste and help where to change the Disabled look-like part.

Can anyone help me?

Can you please explain what is it that you exactly want to achieve? You want to apply a new template to WPF DataGrid and you want the current control template of `DataGrid` to override on top of it? — WPF-it, Mar 14 '12 at 09:51
to use the same template , only to change the IsEnabled foreground from gray to green (override this part) — Programer, Mar 14 '12 at 14:01

Luke Forder · Accepted Answer · 2012-03-14T14:53:40.947

EDIT: It's been pointed out that all the default control templates are available at MSDN which makes the below relevant, but I'll leave it here for interest.

Given an instance of a control you get serialize the markup for the control template using the System.Windows.Markup.XamlWriter class.

To get a control template:

string markup = System.Windows.Markup.XamlWriter.Save(control.Template);

To get a complete dump (including triggers etc) of the control template use.

        StringBuilder markupBuilder = new StringBuilder();

        XmlWriter writer = XmlWriter.Create(markupBuilder);

        System.Windows.Markup.XamlDesignerSerializationManager manager = 
            new System.Windows.Markup.XamlDesignerSerializationManager(writer);

        manager.XamlWriterMode = System.Windows.Markup.XamlWriterMode.Value;

        // data grid named dataGrid1
        var template = dataGrid1.Template;

        System.Windows.Markup.XamlWriter.Save(dataGrid1.Template, manager);

        string markup = markupBuilder.ToString();

If you just looking to change the foreground color of the DataGrid when it's disabled, you should be able to use styles together with triggers rather than replacing the entire template.

<DataGrid>
    <DataGrid.Resources>
        <Style
            TargetType="{x:Type DataGridColumnHeader}">
            <Style.Triggers>
                <DataTrigger
                    Binding="{Binding IsEnabled, RelativeSource={RelativeSource AncestorType={x:Type DataGrid}}}"
                    Value="False">
                    <Setter
                        Property="Foreground"
                        Value="Green" />
                </DataTrigger>
            </Style.Triggers>
        </Style>
        <Style
            TargetType="{x:Type DataGridCell}">
            <Style.Triggers>
                <DataTrigger
                    Binding="{Binding IsEnabled, RelativeSource={RelativeSource AncestorType={x:Type DataGrid}}}"
                    Value="False">
                    <Setter
                        Property="Foreground"
                        Value="Green" />
                </DataTrigger>
            </Style.Triggers>
        </Style>
    </DataGrid.Resources>
    <!-- Column Definitions -->
</DataGrid>

Adding the above 2 styles to the DataGrid's resources collection will, set the foreground of each column header and data row cell to green when the DataGrid is disabled.

That kind of work is unnecessary, you can get all the templates on MSDN, see http://stackoverflow.com/questions/1559261/control-template-for-existing-controls-in-wpf — H.B., Mar 14 '12 at 13:11
Also, Expression Blend allows you to create copies of the templates of any control... — myermian, Mar 14 '12 at 13:46
Thanks. I tried: than pasting your xaml above but it destroys my grid, meaning it does not function as before - no rows are visible etc. — Programer, Mar 14 '12 at 14:15
Place the DataGrid.Resources element directly within the DataGrid element. — Luke Forder, Mar 14 '12 at 14:56
I did not put it into the dataGrid, I added the two styles sepratley in my ResourceDictionary (under DataGrid.Resource it throws an exception). ThankS! — Programer, Mar 14 '12 at 14:57

score 0 · Answer 2 · answered Mar 14 '12 at 08:46

0

To define the disabled behavior of any control, you should change the Disabled visual state accordingly in the control template.

answered Mar 14 '12 at 08:46

andrew

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i dont see it...is the one posted here correct? http://social.msdn.microsoft.com/Forums/en/wpf/thread/8e6f3c70-f65f-4152-9469-9ae3e9239126 if so where is the part you said? – Programer Mar 14 '12 at 10:00

Deriving (Expanding) a Control Template in WPF

2 Answers2