multiprocessing.Pool already has a shared result-queue, there is no need to additionally involve a Manager.Queue. Manager.Queue is a queue.Queue (multithreading-queue) under the hood, located on a separate server-process and exposed via proxies. This adds additional overhead compared to Pool's internal queue. Contrary to relying on Pool's native result-handling, the results in the Manager.Queue also are not guaranteed to be ordered.
The worker processes are not started with .apply_async(), this already happens when you instantiate Pool. What is started
when you call pool.apply_async() is a new "job". Pool's worker-processes run the multiprocessing.pool.worker-function under the hood. This function takes care of processing new "tasks" transferred over Pool's internal Pool._inqueue and of sending results back to the parent over the Pool._outqueue. Your specified func will be executed within multiprocessing.pool.worker. func only has to return something and the result will be automatically send back to the parent.
.apply_async() immediately (asynchronously) returns a AsyncResult object (alias for ApplyResult). You need to call .get() (is blocking) on that object to receive the actual result. Another option would be to register a callback function, which gets fired as soon as the result becomes ready.
from multiprocessing import Pool
def busy_foo(i):
"""Dummy function simulating cpu-bound work."""
for _ in range(int(10e6)): # do stuff
pass
return i
if __name__ == '__main__':
with Pool(4) as pool:
print(pool._outqueue) # DEMO
results = [pool.apply_async(busy_foo, (i,)) for i in range(10)]
# `.apply_async()` immediately returns AsyncResult (ApplyResult) object
print(results[0]) # DEMO
results = [res.get() for res in results]
print(f'result: {results}')
Example Output:
<multiprocessing.queues.SimpleQueue object at 0x7fa124fd67f0>
<multiprocessing.pool.ApplyResult object at 0x7fa12586da20>
result: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
Note: Specifying the timeout-parameter for .get() will not stop the actual processing of the task within the worker, it only unblocks the waiting parent by raising a multiprocessing.TimeoutError.