Spring 3.1 Tomcat 6.*
I'm working on making a Spring 3.1 webapp, authenticating with LDAP.
I tested the LDAP credentials (username, password, ldap URL, search pattern ) with a JNDI styled Java program I wrote (quoted below ). That program worked, dumped all of the users attributes, including the password, which seems to be encrypted on the LDAP server.
When I try to login with the same credentials in Spring 3.1 I get the error message "Bad Credentials".
I got this message in the logs:
DEBUG [org.springframework.security.authentication.ProviderManager:authenticate] (ProviderManager.java:152) - Authentication attempt using org.springframework.security.ldap.authentication.LdapAuthenticationProvider
DEBUG [org.springframework.security.ldap.authentication.AbstractLdapAuthenticationProvider:authenticate] (AbstractLdapAuthenticationProvider.java:51) - Processing authentication request for user: John.A.Smith
DEBUG [org.springframework.security.ldap.authentication.BindAuthenticator:bindWithDn] (BindAuthenticator.java:108) - Attempting to bind as uid=John.A.Smith,ou=People,o=acme.com,o=acme.com
DEBUG [org.springframework.security.ldap.DefaultSpringSecurityContextSource$1:setupEnvironment] (DefaultSpringSecurityContextSource.java:76) - Removing pooling flag for user uid=John.A.Smith,ou=People,o=acme.com,o=acme.com
DEBUG [org.springframework.security.ldap.authentication.BindAuthenticator:handleBindException] (BindAuthenticator.java:152) - Failed to bind as uid=John.A.Smith,ou=People,o=acme.gov: org.springframework.ldap.AuthenticationException: [LDAP: error code 32 - No Such Object]; nested exception is javax.naming.AuthenticationException: [LDAP: error code 32 - No Such Object]
DEBUG [org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter:unsuccessfulAuthentication] (AbstractAuthenticationProcessingFilter.java:340) - Authentication request failed: org.springframework.security.authentication.BadCredentialsException: Bad credentials
In my *-security.xml I tried using tags to make a password comparison and encoding happen, but it didn't help. I tried using md4,md5,plaintext,sha,sha-256,{ssha},{sha} to no avail.
   <s:authentication-manager>
        <s:ldap-authentication-provider user-dn-pattern="uid={0},ou=People,o=noaa.gov" >
          <s:password-compare hash="md5">
            <s:password-encoder hash="md5"/>
          </s:password-compare>
        </s:ldap-authentication-provider>
      </s:authentication-manager>
My networking group is a big, slow, bureaucratic org. Is there a way I can tell what encoding they use, if any, without contacting them?
Any ideas of things I could check out?
This is my *-security.xml as of my last attempt and the java LDAP demo I WAS able to connect with
Thanks.
My *-security.xml file:
<beans xmlns="http://www.springframework.org/schema/beans"  
  xmlns:s="http://www.springframework.org/schema/security"  
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"  
  xsi:schemaLocation="http://www.springframework.org/schema/beans  
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd  
    http://www.springframework.org/schema/security  
    http://www.springframework.org/schema/security/spring-security-3.1.xsd">  
  <s:http auto-config="true" use-expressions="true">  
    **<s:intercept-url pattern="/welcome*" access="isAuthenticated()" />** 
    <s:form-login login-page="/login" default-target-url="/welcome"  
      authentication-failure-url="/loginfailed" />  
    <s:logout logout-success-url="/logout" />  
  </s:http>  
  <s:ldap-server url = "ldap://ldap-itc.sam.acme.com:636/o=acme.com"/>  
  <s:authentication-manager>
    <s:ldap-authentication-provider user-dn-pattern="uid={0},ou=People,o=noaa.gov" />
  </s:authentication-manager>
</beans>  
Here is the JNDI style LDAP Java program that WORKS with the same credentials:
import javax.naming.*;  
import javax.naming.directory.*;  
import java.util.*;  
import java.sql.*;  
public class LDAPDEMO {  
    public static void main(String args[]) {  
        String lcf                = "com.sun.jndi.ldap.LdapCtxFactory";  
        String ldapurl            = "ldap://ldap-itc.sam.acme.com:636/o=acme.com";  
        String loginid            = "John.A.Smith";  
        String password           = "passowordforjohn";  
        DirContext ctx            = null;  
        Hashtable env             = new Hashtable();  
        Attributes attr           = null;  
        Attributes resultsAttrs   = null;  
        SearchResult result       = null;  
        NamingEnumeration results = null;  
        int iResults              = 0;  
        env.put(Context.INITIAL_CONTEXT_FACTORY, lcf);  
        env.put(Context.PROVIDER_URL, ldapurl);  
        env.put(Context.SECURITY_PROTOCOL, "ssl");  
        env.put(Context.SECURITY_AUTHENTICATION, "simple");  
        env.put(Context.SECURITY_PRINCIPAL, "uid=" + loginid + ",ou=People,o=acme.com");  
        env.put(Context.SECURITY_CREDENTIALS, password);  
        try {  
            ctx     = new InitialDirContext(env);  
            attr    = new BasicAttributes(true);  
            attr.put(new BasicAttribute("uid",loginid));  
            results = ctx.search("ou=People",attr);  
            while (results.hasMore()) {  
                result       = (SearchResult)results.next();  
                resultsAttrs = result.getAttributes();  
                for (NamingEnumeration enumAttributes  = resultsAttrs.getAll(); enumAttributes.hasMore();) {  
                    Attribute a = (Attribute)enumAttributes.next();  
                    System.out.println("attribute: " + a.getID() + " : " + a.get().toString());  
                }// end for loop  
                iResults++;  
            }// end while loop  
            System.out.println("iResults == " + iResults);  
        }// end try  
        catch (Exception e) {  
            e.printStackTrace();  
        }  
    }// end function main()  
}// end class LDAPDEMO  
Solution
This comment from Luke Taylor helped me get my configuration working:
Your configuration is wrong in that you have "o=acme.com" in the LDAP server URL and are also using "o=acme.com" in the user DN pattern.
I took the "o=acme.com" out of the DN pattern and the LDAP worked. I had originally put the "o=acme.com" in both the LDAP URL and the DN pattern because I am new to Spring 3.1 and LDAP, and that is similar to how it is/was done in the Java JNDI version of the LDAP demo I wrote based on the legacy code I am replacing.
Here is the final, working version of my *-security.xml
<beans xmlns="http://www.springframework.org/schema/beans"  
  xmlns:s="http://www.springframework.org/schema/security"  
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"  
  xsi:schemaLocation="http://www.springframework.org/schema/beans  
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd  
    http://www.springframework.org/schema/security  
    http://www.springframework.org/schema/security/spring-security-3.1.xsd">  
  <s:http auto-config="true" use-expressions="true">  
    **<s:intercept-url pattern="/welcome*" access="isAuthenticated()" />** 
    <s:form-login login-page="/login" default-target-url="/welcome"  
      authentication-failure-url="/loginfailed" />  
    <s:logout logout-success-url="/logout" />  
  </s:http>  
  <s:ldap-server url = "ldap://ldap-itc.sam.acme.com:636/o=acme.com"/>  
  <s:authentication-manager>
    <s:ldap-authentication-provider user-dn-pattern="uid={0},ou=People" />
  </s:authentication-manager>
</beans>  
I'm going to explore his other comment and see if I can put the password encoding back in or if I need to.
 
     
    