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My old freebsd 8.0 has the following configuration (in the /etc/rc.conf) for the xx jail:

jail_xx_hostname="xx.example.com"
jail_xx_rootdir="/jails/xx"

#networking setup
jail_xx_ip="sis0|1.2.3.4,re0|10.10.10.4"
jail_xx_ip_multi0="tun0|10.5.0.1 10.5.0.2 mtu 1500 255.255.255.255"
jail_xx_devfs_ruleset="devfsrules_jail_xx"

E.g. have attached two different NICs (and plus one tun device to the jail).

How to achieve the same networking setup in Freebsd 10.2 using the /etc/jail.conf?

I tried:

xx {
    ip4.addr = "sis0|1.2.3.4,re0|10.10.10.4"
}

but got an error:

jail: xx: ip4.addr: not an IPv4 address: re0|10.10.10.4

Could someone help me how to attach two network interfaces (e.g. sis0 and re0)to the jail in FreeBSD 10.2?

Whrere it is documented? I'm absolutely lost with the new jail.conf based jail configs... :(

please, help.

kobame
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1 Answers1

2

Just figured out the solution.

The documentation(jail.conf (5)) says the following example

A comma-separated list of values may be set in a single statement, or an existing parameter list may be appended to using ``+='':

   ip4.addr = 10.1.1.1, 10.1.1.2, 10.1.1.3;

   ip4.addr = 10.1.1.1;
   ip4.addr += 10.1.1.2;
   ip4.addr += 10.1.1.3;

While the simple:

ip4.addr = "sis0|1.2.3.4,re0|10.10.10.4";

doesn't works, when I used the += form, it finally does what i want. So, the solution is:

xx {
    ...
    interface = "sis0";
    ip4.addr += "sis0|1.2.3.4";
    ip4.addr += "re0|10.10.10.4";
    ...
}
kobame
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