I would like to check if a java file exists on the PC and if it does, get the path of the file (excluding the filename) and use it in a variable. I need to do this using a batch file.
I have gotten as far as the following command which displays the full path of the .exe file:
for %i in (java.exe) do @echo. %~$PATH:i
The result being:
C:\Program Files\Common Files\Oracle\Java\javapath\java.exe
However, I'm unable to proceed further, as I need to extract the path, excluding the filename. Alternatively, there might be a command which just returns the path of the folder.
Can someone please help me out?
