It doesn't change value in path or java -version doesn't change in current instance of cmd
You have to restart cmd for the changes to take effect as a cmd shell inherits it environment from the parent process.
So what is the correct way to switch between Java versions from the command line?
Use a set of batch files, as follows:
Being a Java developer, I always compile and test my code on different Java versions. But switching between them is a huge problem. So finally I found an easy method to do this. You have to create following batch files and place them in directory you open your command line in or in SYSTEM PATH. You can use you favorite text editor to create these files.
jdk14.bat
@echo off
echo Setting JAVA_HOME
set JAVA_HOME=C:\j2sdk1.4.2_12
echo setting PATH
set PATH=C:\j2sdk1.4.2_12\bin;%PATH%
echo Display java version
java -version
jdk15.bat
@echo off
echo Setting JAVA_HOME
set JAVA_HOME=C:\Program Files\Java\jdk1.5.0_12
echo setting PATH
set PATH=C:\Program Files\Java\jdk1.5.0_12\bin;%PATH%
echo Display java version
java -version
jdk16.bat
@echo off
echo Setting JAVA_HOME
set JAVA_HOME=C:\Program Files\Java\jdk1.6.0_11
echo setting PATH
set PATH=C:\Program Files\Java\jdk1.6.0_11\bin;%PATH%
echo Display java version
java -version
Make sure you assign the appropriate JAVA_HOME value in batch files, according to your Java installation. Whenever you want to switch between Java versions, just run the respective batch file and you are done.
Note: JAVA_HOME and the path to java must always refer to the exact same version of the JDK. If you mix them up, unpredictable things will happen!
Source Switch between different JDK versions in Windows | Oracle Pranav's Blog