I have some videos files where a few frames were missing. I can verify that by playing it in a video player and advance frame-by-frame, or by extracting all frames with ffpeg then check the output images
ffmpeg -loglevel trace -i myfile.mp4 myframes/frame%5d.png
At the end of the extraction I can see something like
frame= 2260 fps= 24 q=-0.0 Lsize=N/A time=00:01:15.33 bitrate=N/A dup=74 drop=0 speed=0.812x
video:2714746kB audio:0kB subtitle:0kB other streams:0kB global headers:0kB muxing overhead: unknown
Input file #0 (myfile.mp4):
Input stream #0:0 (video): 2221 packets read (57126959 bytes); 2186 frames decoded;
Total: 2221 packets (57126959 bytes) demuxed
Output file #0 (myframes/frame%5d.png):
Output stream #0:0 (video): 2260 frames encoded; 2260 packets muxed (2779899741 bytes);
Total: 2260 packets (2779899741 bytes) muxed
2186 frames successfully decoded, 0 decoding errors
We can see dup=74 which means there are 74 duplicated frames. There are also 74 lines containing *** 1 dup! in the output log. However there's no information about those frames. How can I get the frame number (or time) of the duplicated frames? And why are there only 2221 packets being demuxed when the total number of muxed packets is already correct: 2186 + 74 = 2260?
