4

I have a cron job which runs every five minutes all day long.

I want to stop this cron job running on Sundays between 4pm and 5pm - it should start again after this time.

How can I script this?

wonea
  • 1,877
akd
  • 41

3 Answers3

4

Stick this at the top of your cron job script (modified as you need)...

if [[ $(date +%u) -eq 7 && $(date +%H) -eq 16 ]]; then
  echo "I don't run at this time"
  exit 1
fi
echo "Something to do at other times here..."

The first instance of "date" returns the day of week (Sunday = 7), the second returns the hour (16 = 4.00pm - 4.59pm). If the script finds that it's currently day 7 and hour 16, it will exit.

Linker3000
  • 28,240
4

What about:

*/5 * * * * job.sh > /dev/null

00 16 * * 0 touch /tmp/stopJob.lck
00 17 * * 0 rm -f /tmp/stopJob.lck

In job.sh just quit if the file exists:

if [ -f /tmp/stopJob.lck ] 
then 
  exit
fi
Gareth
  • 19,080
DaSteph
  • 64
0

You may not need much if your cron job runs a script and you can make it check for the absence of a process set up to run between 4PM and 5PM on Sundays

For example, I use a cron job every 15 minutes which invokes rsync but only if rsync is not already running.

It uses the pidof command to check if a particular process id is running:

PID=$(pidof rsync)

if [ -z $PID ]
then 
    rsync -avz ....
fi

You will need to work out the details for your particular situation. I present it now as an idea to think about.

pavium
  • 6,490