For example, I have date: 4 August 1993 and I want to add 348 days to it, how can I do it in bash?
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35
Just use the date command with -d option:
$ date -d "1983-08-04 348 days"
Tue Jul 17 00:00:00 BST 1984
You can change the output format if you want:
$ date -d "1983-08-04 2 days" +%Y-%m-%d
1983-08-06
David Webb
- 12,294
19
In bash on Mac OS X, you can do this:
date -j -v +348d -f "%Y-%m-%d" "1993-08-04" +%Y-%m-%d
Output: 1994-07-18
Tom Söderlund
- 311
1
Here is a little more complex usage of this:
for i in `seq 1 5`;
do;
date -d "2014-02-01 $i days" +%Y-%m-%d;
done;
or with pipes:
seq 1 5 | xargs -I {} date -d "2014-02-01 {} days" +%Y-%m-%d
Bohdan
- 111