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Can you help me to find the PID's user name?

Sometimes my server has high load. When I run top -c, I cannot even find the owner of a process which is causing load on the server.

Aulis Ronkainen
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Ranjithkumar T
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6 Answers6

60

I'm surprised nobody has put this up yet:

Try the -p option of the ps command.

For instance, if you have PID 1234, run:

ps -u -p 1234

The -u was added to include the username in the output.

You can then use grep or awk, etc. to extract the info you want.

Matthias Braun
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jwd
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10

/proc/processID/status will have the information about user's ID which you can use to find the username.

This does the same:

uid=$(awk '/^Uid:/{print $2}' /proc/YOUR_PROCESS_ID/status)
getent passwd "$uid" | awk -F: '{print $1}'

Replace YOUR_PROCESS_ID with your process ID number.

grawity
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P.P
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7

Get only username from a PID:

PID=136323
USERNAME="$( ps -o uname= -p "${PID}" )"

You can also combine it with a pgrep. In this example we show all usernames executing some .php file: 

pgrep -f '\.php' | xargs -r ps -o uname= -p | sort -u

Find only one username running a certain unique process:

USERNAME="$( pgrep -nf 'script\.php' | xargs -r ps -o uname= -p )
Jeroen Vermeulen
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4

I think the shortest way is:

id -nu </proc/<pid>/loginuid

The /proc/<pid>/loginuid file has the uid number of the user running the process; id -nu reads uid from stdin and returns a user name.

Diego
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What do you want exactly? On my system, if I run 'top -c' I get:

  PID USER      PR  NI  VIRT  RES  SHR S   %CPU %MEM    TIME+  COMMAND                                                                                                                        
  2873 matt      20   0 3022m 1.6g 1.6g S     22 21.6   2245:42 /usr/lib/virtualbox/VirtualBox --comment ESX5-1 --startvm 4fd78ee9-739a-4d53-a0ce-4f9819ab9411 --no-startvm-errormsgbox        
  29764matt      20   0 2779m 1.4g 1.3g S      5 18.4 210:33.51 /usr/lib/virtualbox/VirtualBox --comment win2008-2 --startvm 202ec2b7-ae12-40e9-af76-2be429e553d7 --no-startvm-errormsgbox     
  17281root      20   0     0    0    0 S      2  0.0   0:05.90 [kworker/u:2]

So the PID (processus/task identifier) is the first column, and the user account the processus runs under is the second column

mbarthelemy
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0

You can use the following command.

use ps aux| grep "pid"

Also,

ls -ld /proc/"pid"/exe
Toto
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digvijay
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