89

I have a spreadsheet with a large number of cells containing hyperlinks with display text different than the hyperlink location

ie:

cell location: A1

display text = "Site Info"

hyperlink location = "http://www.mylocation.com"

Is there an excel formula that allows me to access the text string of the hyperlink location?

Ideally it would look like this:

FORMULA(A1) = "http://www.mylocation.com"

Gigamosh57
  • 1,025
  • 2
  • 8
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5 Answers5

75

You can use a macro:

  • Open up a new workbook.
  • Get into VBA (Press Alt+F11)
  • Insert a new module (Insert > Module)
  • Copy and Paste the Excel user defined function below
  • Get out of VBA (Press Alt+Q)
  • Use this syntax for this custom Excel function: =GetURL(cell,[default_value])

     Function GetURL(cell As range, Optional default_value As Variant)
     'Lists the Hyperlink Address for a Given Cell
     'If cell does not contain a hyperlink, return default_value
          If (cell.range("A1").Hyperlinks.Count <> 1) Then
              GetURL = default_value
          Else
              GetURL = cell.range("A1").Hyperlinks(1).Address
          End If
    End Function
    
Igor O
  • 851
46

I only needed to extract the address from a single cell's value so I found this small function handy:

Instead of a "brute force" macro, you could also create a user-defined function that would extract and return the URL for any hyperlink at which it was pointed:

Function GetURL(rng As Range) As String
     On Error Resume Next
     GetURL = rng.Hyperlinks(1).Address 
End Function

In this case you can place it where you want. If you want, for example, the URL from a hyperlink in A1 to be listed in cell C25, then in cell C25 you would enter the following formula:

=GetURL(A1)

http://excel.tips.net/T003281_Extracting_URLs_from_Hyperlinks.html

Matthew Lock
  • 4,757
3
function EXTRACT_URL(input) {

  var range = SpreadsheetApp.getActiveSheet().getRange(input);
  var re = /^.+?\(\"(.+?)\",.+?$/;
  if (input.indexOf(':') != -1) {
    var formulas = range.getFormulas();
    for (var i in formulas) {
      for (var j in formulas[i]) {
        formulas[i][j] = formulas[i][j].replace(re, "$1");
      }
    }
    return formulas;
  } else {
    return range.getFormula().replace(re, "$1");
  }

}
fixer1234
  • 28,064
3
  1. Open up a new workbook.
  2. Get into VBA with Alt+F11 (Fn + Opt + F11 for MAC)
  3. Insert a new module (Insert > Module)
  4. Copy and Paste the Excel user defined function below
  5. Press F5 and click “Run” Get out of VBA (Press Alt+Q)
Sub ExtractHL()
Dim HL As Hyperlink
For Each HL In ActiveSheet.Hyperlinks
HL.Range.Offset(0, 1).Value = HL.Address
Next
End Sub
Gabriel Fair
  • 4,093
3

I had the same issue as @SAL

I found that the .Hyperlink object actually splits the address into .Address and .SubAddress if it encounters a delimiter. "#" is one such delimiter (I don't know if there are others).

See @gilly3 's comment above and this other StackOverflow question: hyperlinks(1).address only returning a partial address

Also Microsoft's (incomplete) documentation on .SubAddress: Hyperlink.SubAddress property

One thing not mentioned anywhere is that the "#" delimiter is not included in either .Address or .SubAddress so if you want an address that will actually work as a full URL, you have to add the "#" delimiter back in.

With that, I modified @Matthew Lock's code as follows, also including the possibility of multiple hyperlinks being stored from @Igor O and my addition of "#":

 Function getURL(rng As Range) As String
     On Error Resume Next
     fullURL = ""
     For Each HL In rng.Hyperlinks
     If Len(HL.SubAddress) &gt; 0 Then
         fullURL = fullURL &amp; HL.Address &amp; &quot;#&quot; &amp; HL.SubAddress &amp; &quot; &quot;
     Else
         fullURL = fullURL &amp; HL.Address &amp; &quot; &quot;
     End If

 Next

 getURL = fullURL

End Function

This should return a text string of all hyperlinks in full (I added a space at the end so if there's more than one, they are separated).

Trashman
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