How to recursively chmod all directories except files?

Question

How to chmod 755 all directories but not files (recursively)?

Inversely, how to chmod only files (recursively) but no directories?

score 1109 · Accepted Answer · edited Nov 04 '23 at 10:32

To recursively give directories read&execute privileges:

find /path/to/base/dir -type d -exec chmod 755 {} +

To recursively give files read privileges:

find /path/to/base/dir -type f -exec chmod 644 {} +

Or, if there are many objects to process:

chmod 755 $(find /path/to/base/dir -type d)
chmod 644 $(find /path/to/base/dir -type f)

Note these recipes may not work correctly if you have whitespace in your input [also true of the xargs examples below].

Or, to reduce chmod spawning:

find /path/to/base/dir -type d -print0 | xargs -0 chmod 755 
find /path/to/base/dir -type f -print0 | xargs -0 chmod 644

score 397 · Answer 2 · edited Oct 18 '23 at 07:23

A common reason for this sort of thing is to set directories to 755 but files to 644. In this case there's a slightly quicker way than nik's find example:

chmod -R u+rwX,go+rX,go-w /path

Meaning:

-R = recursively;
u+rwX = Users can read, write and execute;
go+rX = group and others can read and execute;
go-w = group and others can't write

The important thing to note here is that uppercase X acts differently to lowercase x. In the manual, we can read:

The execute/search bits if the file is a directory or any of the execute/search bits are set in the original (unmodified) mode.

In other words, chmod u+X on a file won't set the execute bit; and chmod g+X will only set it if it's already set for the user.

score 22 · Answer 3 · edited Jun 25 '11 at 08:31

If you want to make sure the files are set to 644 and there are files in the path which have the execute flag, you will have to remove the execute flag first. +X doesn't remove the execute flag from files who already have it.

Example:

chmod -R ugo-x,u+rwX,go+rX,go-w path

Update: this appears to fail because the first change (ugo-x) makes the directory unexecutable, so all the files underneath it are not changed.

score 8 · Answer 4 · answered Feb 21 '18 at 11:58

To recursively give directories read&execute privileges:

find /path/to/base/dir -type d -exec chmod 755 {} \;

To recursively give files read privileges:

find /path/to/base/dir -type f -exec chmod 644 {} \;

Better late than never let me upgrade nik's answer on the side of correctness. My solution is slower, but it works with any number of files, with any symbols in filenames, and you can run it with sudo normally (but beware that it might discover different files with sudo).

score 4 · Answer 5 · edited Apr 25 '19 at 02:56

I decided to write a little script for this myself.

Recursive chmod script for dirs and/or files — Gist:

chmodr.sh

#!/bin/sh
# 
# chmodr.sh
#
# author: Francis Byrne
# date: 2011/02/12
#
# Generic Script for recursively setting permissions for directories and files
# to defined or default permissions using chmod.
#
# Takes a path to recurse through and options for specifying directory and/or 
# file permissions.
# Outputs a list of affected directories and files.
# 
# If no options are specified, it recursively resets all directory and file
# permissions to the default for most OSs (dirs: 755, files: 644).

# Usage message
usage()
{
  echo "Usage: $0 PATH -d DIRPERMS -f FILEPERMS"
  echo "Arguments:"
  echo "PATH: path to the root directory you wish to modify permissions for"
  echo "Options:"
  echo " -d DIRPERMS, directory permissions"
  echo " -f FILEPERMS, file permissions"
  exit 1
}

# Check if user entered arguments
if [ $# -lt 1 ] ; then
 usage
fi

# Get options
while getopts d:f: opt
do
  case "$opt" in
    d) DIRPERMS="$OPTARG";;
    f) FILEPERMS="$OPTARG";;
    \?) usage;;
  esac
done

# Shift option index so that $1 now refers to the first argument
shift $(($OPTIND - 1))

# Default directory and file permissions, if not set on command line
if [ -z "$DIRPERMS" ] && [ -z "$FILEPERMS" ] ; then
  DIRPERMS=755
  FILEPERMS=644
fi

# Set the root path to be the argument entered by the user
ROOT=$1

# Check if the root path is a valid directory
if [ ! -d $ROOT ] ; then
 echo "$ROOT does not exist or isn't a directory!" ; exit 1
fi

# Recursively set directory/file permissions based on the permission variables
if [ -n "$DIRPERMS" ] ; then
  find $ROOT -type d -print0 | xargs -0 chmod -v $DIRPERMS
fi

if [ -n "$FILEPERMS" ] ; then
  find $ROOT -type f -print0 | xargs -0 chmod -v $FILEPERMS
fi

It basically does the recursive chmod but also provides a bit of flexibility for command line options (sets directory and/or file permissions, or exclude both it automatically resets everything to 755-644). It also checks for a few error scenarios.

I also wrote about it on my blog.

score 2 · Answer 6 · answered Nov 05 '20 at 14:06

I post my solution because I don't see an almost-every cases solution using only chmod:

Only chmod : smooth permissions on files and dirs

For my example I created multiple files with different permissions:

> tree -p chmodtests/
chmodtests/
├── [drwxr-xr-x]  aa/
│   ├── [drwxr-xr-x]  a1/
│   │   ├── [-r--r--r--]  read_only
│   │   ├── [-rw-rw-rw-]  read_w
│   │   └── [-rwxrwxrwx]  read_wx*
│   ├── [drwxr-xr-x]  a2/
│   ├── [-r--------]  read_only
│   ├── [-rw-------]  read_w
│   └── [-rwx------]  read_wx*
└── [drwxr-xr-x]  bb/
4 directories, 6 files

then apply this command:

chmod -vR a=r-wx,u=wr,a+X chmodtests/

output:

mode of 'chmodtests/' retained as 0755 (rwxr-xr-x)
mode of 'chmodtests/aa' retained as 0755 (rwxr-xr-x)
mode of 'chmodtests/aa/a1' retained as 0755 (rwxr-xr-x)
mode of 'chmodtests/aa/a1/read_only' changed from 0444 (r--r--r--) to 0644 (rw-r--r--)
mode of 'chmodtests/aa/a1/read_w' changed from 0666 (rw-rw-rw-) to 0644 (rw-r--r--)
mode of 'chmodtests/aa/a1/read_wx' changed from 0777 (rwxrwxrwx) to 0644 (rw-r--r--)
mode of 'chmodtests/aa/read_only' changed from 0400 (r--------) to 0644 (rw-r--r--)
mode of 'chmodtests/aa/a2' retained as 0755 (rwxr-xr-x)
mode of 'chmodtests/aa/read_w' changed from 0600 (rw-------) to 0644 (rw-r--r--)
mode of 'chmodtests/aa/read_wx' changed from 0700 (rwx------) to 0644 (rw-r--r--)
mode of 'chmodtests/bb' retained as 0755 (rwxr-xr-x)

result: all files are 644; all dirs are 755

> tree -p chmodtests/
chmodtests/
├── [drwxr-xr-x]  aa/
│   ├── [drwxr-xr-x]  a1/
│   │   ├── [-rw-r--r--]  read_only
│   │   ├── [-rw-r--r--]  read_w
│   │   └── [-rw-r--r--]  read_wx
│   ├── [drwxr-xr-x]  a2/
│   ├── [-rw-r--r--]  read_only
│   ├── [-rw-r--r--]  read_w
│   └── [-rw-r--r--]  read_wx
└── [drwxr-xr-x]  bb/

Explanation part

tl;dr explanation:

this command removes all execution/search on files and directories and then add execution/search only for dirs

chmod -vR : verbose and recursive

a=r-wx:

a: meaning all (user, group and other)
=: set permissions to (do not add nor remove)
r-wx: read only permissions

u=wr: user can read and write

a+X: add execution/search only for directories (for all types u,g,o)

Other example

Now let's say I only want 600 for files and 700 for dirs:

chmod -vR a=-rwx,u=rw,u+X chmodtests/

Limits

With this method you cannot set r and w differently for file and dirs.

E.g. you cannot have the following

drwxr-xr-x dir/
-r-------- dir/myfile

hth

score 2 · Answer 7 · answered Mar 26 '13 at 04:37

Try this python script; it requires no spawning of processes and does only two syscalls per file. Apart from an implementation in C, it will probably be the fastest way of doing it (I needed it to fix a filesystem of 15 million files which were all set to 777)

#!/usr/bin/python3
import os
for par, dirs, files in os.walk('.'):
    for d in dirs:
        os.chmod(par + '/' + d, 0o755)
    for f in files:
        os.chmod(par + '/' + f, 0o644)

In my case, a try/catch was required around the last chmod, since chmodding some special files failed.

score 0 · Answer 8 · answered Jul 15 '22 at 19:00

Built on top of nik's answer for convenience while still being minimal:

#!/bin/bash
me=basename &quot;$0&quot;
if [[ -z $3 || $1 == "help" || $1 == "-h" || $1 == "--help" ]]; then
    echo "Usage: $me <directory_permissions> <file_permissions> <path> [ -s ]"
    exit 0
fi
terminator=+
if [[ $1 == "-s" ]]; then
    terminator=;
fi
find $3 -type f -exec chmod $2 '{}' $terminator
find $3 -type d -exec chmod $1 '{}' $terminator

The -s will enable secure/safe mode which is required if you deal with a ton of files, because the chained command would exceed the argument limit of the individual command.

This implementation is not prone to spaces in paths.

Eduard Florinescu · Answer 9 · 2018-10-10T05:58:43.723

-1

You can also use tree:

tree -faid /your_directory | xargs -L1 -I{} bash -c 'sudo chmod 755 "$1"' -- '{}'

and if you want to also view the folder add an echo

 tree -faid /your_directory | xargs -L1 -I{} bash -c 'sudo chmod 755 "$1" && echo$1' -- '{}'

edited Oct 10 '18 at 05:58

answered Feb 16 '18 at 09:34

Eduard Florinescu

3,186

score -3 · Answer 10 · answered Jan 29 '10 at 11:56

You could use the following bash script as an example. Be sure to give it executable permissions (755). Simply use ./autochmod.sh for the current directory, or ./autochmod.sh <dir> to specify a different one.

#!/bin/bash

if [ -e $1 ]; then
    if [ -d $1 ];then
        dir=$1
    else
        echo "No such directory: $1"
        exit
    fi
else
    dir="./"
fi

for f in $(ls -l $dir | awk '{print $8}'); do
    if [ -d $f ];then
        chmod 755 $f
    else
        chmod 644 $f
    fi
done

How to recursively chmod all directories except files?

10 Answers10

Only chmod : smooth permissions on files and dirs

Explanation part

Other example

Limits

Linked

Related