Get string after character

Question

I have a string that looks like this:

 GenFiltEff=7.092200e-01

Using bash, I would like to just get the number after the = character. Is there a way to do this?

This should be reopened. `How to grep` is asking how you do it with grep, this question is asking how to get string after character... not tied with `grep`. — Jamie Hutber, Dec 17 '18 at 12:19

score 168 · Answer 1 · answered Mar 01 '13 at 02:09

168

Use parameter expansion, if the value is already stored in a variable.

$ str="GenFiltEff=7.092200e-01"
$ value=${str#*=}

Or use read

$ IFS="=" read name value <<< "GenFiltEff=7.092200e-01"

Either way,

$ echo $value
7.092200e-01

answered Mar 01 '13 at 02:09

chepner

45

If the string has more than one "=": `${str##*=} to get from the last match. ${str#*=} to get from the first match. ${str%%=*} to get until the first match. ${str%=*} to get until the last match.` [String Manipulation @ tldp.org] (http://tldp.org/LDP/abs/html/string-manipulation.html) – lepe Dec 27 '14 at 04:36
I didnt get the second solution to work: `$ IFS="=" read name value <<< "GenFiltEff=7.092200e-01"` using bash 4.4.5 – sn1ckers Jan 24 '17 at 13:39
Works fine for me in 4.4.5. If you cannot figure out the problem, though, please open a new question that includes the result you *do* get. – chepner Jan 24 '17 at 13:52
2

It would be great if this answer explained itself in more detail. What exactly do each of `#*=` do here? – buildsucceeded Feb 15 '17 at 17:09
1

The `#` operator omits the shortest prefix that matches the pattern `*=` from the expansion of `$str`. – chepner Feb 15 '17 at 17:39

score 134 · Accepted Answer · edited Mar 13 '20 at 18:55

134

For the text after the first = and before the next =

cut -d "=" -f2 <<< "$your_str"

or

sed -e 's#.*=\(\)#\1#' <<< "$your_str"

For all text after the first = regardless of if there are multiple =

cut -d "=" -f2- <<< "$your_str"

edited Mar 13 '20 at 18:55

Elle H

answered Mar 01 '13 at 01:21

Tuxdude

11

Good for simple cases, however these methods don't play well when there is more than one "=" in the string. Chepner's first solution is simple and more reliable. – lepe Dec 27 '14 at 04:40
The answer is more useful when using | to run commands in a chain then when using variables. – Mohammad Yasir K P Jun 13 '22 at 11:32

score 25 · Answer 3 · answered Mar 01 '13 at 01:26

25

echo "GenFiltEff=7.092200e-01" | cut -d "=" -f2

answered Mar 01 '13 at 01:26

Greg Guida

Note that you can add `-s` flag to display nothing if the delimiter was not present – Jules Sam. Randolph Jul 17 '21 at 16:34

score 6 · Answer 4 · answered Mar 01 '13 at 01:19

6

This should work:

your_str='GenFiltEff=7.092200e-01'
echo $your_str | cut -d "=" -f2

answered Mar 01 '13 at 01:19

jman

score 5 · Answer 5 · answered Mar 01 '13 at 01:23

5

${word:$(expr index "$word" "="):1}

that gets the 7. Assuming you mean the entire rest of the string, just leave off the :1.

answered Mar 01 '13 at 01:23

Explosion Pills

`$value = ${word:$(expr index "$word" "=")}` worked well for me to return everything after the equal sign. – DTrejo Apr 30 '19 at 21:55

5 Answers5