Converting float to char*

Question

How can I convert a float value to char* in C language?

Answer 1

char buffer[64];
int ret = snprintf(buffer, sizeof buffer, "%f", myFloat);

if (ret < 0) {
    return EXIT_FAILURE;
}
if (ret >= sizeof buffer) {
    /* Result was truncated - resize the buffer and retry.
}

That will store the string representation of myFloat in myCharPointer. Make sure that the string is large enough to hold it, though.

snprintf is a better option than sprintf as it guarantees it will never write past the size of the buffer you supply in argument 2.

Answer 2

In Arduino:

//temporarily holds data from vals
char charVal[10];                

//4 is mininum width, 3 is precision; float value is copied onto buff
dtostrf(123.234, 4, 3, charVal);

monitor.print("charVal: ");
monitor.println(charVal);

Answer 3

char array[10];
sprintf(array, "%f", 3.123);

sprintf: (from MSDN)

Answer 4

Long after accept answer.

Use sprintf(), or related functions, as many others have answers suggested, but use a better format specifier.

Using "%.*e", code solves various issues:

• The maximum buffer size needed is far more reasonable with "%.*e", like 18 for float (see below). With "%f", (think fixed-point), sprintf(buf, "%f", FLT_MAX); could need 47+ char. sprintf(buf, "%f", DBL_MAX); may need 317+ char.

• Using ".*" allows code to define the number of decimal places needed to distinguish a string version of float x and it next highest float. For details, see printf width specifier to maintain precision of floating-point value

• Using "%e" allows code to distinguish small floats from each other rather than all printing "0.000000" which is the result when |x| < 0.0000005 with "%f".

Example usage:

#include <float.h>
#define FLT_STRING_SIZE (1+1+1+(FLT_DECIMAL_DIG-1)+1+1+ 4   +1)
                     //  - d .  dddddddd           e - dddd \0

char buf[FLT_STRING_SIZE];
sprintf(buf, "%.*e", FLT_DECIMAL_DIG-1, some_float);

Ideas:
IMO, better to use 2x buffer size for scratch pads like buf[FLT_STRING_SIZE*2].
For added robustness, use snprintf().

---

As a 2nd alterative consider "%.*g". It is like "%f" for values exponentially near 1.0 and like "%e" for others.

Answer 5

typedef union{
    float a;
    char b[4];
} my_union_t;

You can access to float data value byte by byte and send it through 8-bit output buffer (e.g. USART) without casting.

Answer 6

char* str=NULL;
int len = asprintf(&str, "%g", float_var);
if (len == -1)
  fprintf(stderr, "Error converting float: %m\n");
else
  printf("float is %s\n", str);
free(str);

Answer 7

char array[10];
snprintf(array, sizeof(array), "%f", 3.333333);

Answer 8

// float arr to bytes
int arr_len = 3;
float x[3] = {1.123, 2.123, 3.123};
char* bytes = new char[arr_len * sizeof(float)];
memcpy(bytes, x, arr_len * sizeof(float));

// bytes to float arr
float y[3];
memcpy(y, bytes, arr_len * sizeof(float));

Answer 9

Convert float to binary via ascii codes

float u = 2.154328
string s = to_string(u);
char* p = (char*) s;

This stores the characters, 2, .,1, 5, ..., or in binary 00000010,00101110, 00000001, ...