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I've got the default OpenSSL 9.8 (Mac OS X 10.6.8) and decided to install the newest version (1.0.1) via MacPorts (sudo port install openssl).

These are console output of which and whereis commands:

$ whereis openssl
/usr/bin/openssl

(this is default system's one)

$which openssl
/opt/local/bin/openssl

(this is installed via MacPorts)

$ openssl version
OpenSSL 1.0.1c 10 May 2012

(there is mac port's version in PATH)

Why are different paths returned for whereis and which, and is this okay? Is there any way to get equal results?

slhck
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jctim
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1 Answers1

39

In the manpage of whereis, it clearly says (emphasis mine):

The whereis utility checks the standard binary directories for the specified programs, printing out the paths of any it finds.

The path searched is the string returned by the sysctl(8) utility for the ``user.cs_path'' string

Contrary to that, which is the tool commonly used to check where a binary is for your user's path.

The which utility takes a list of command names and searches the path for each executable file that would be run had these commands actually been invoked.

That explains your difference, since /opt/local/bin is not a system-wide "standard" path—after all, MacPorts is a completely optional installation—and sysctl only has /usr/bin:/bin:/usr/sbin:/sbin in its user.cs_path per default.

In general, stick to which or which -a to find a binary rather than using whereis.

You can theoretically change user.cs_path through

sysctl -w user.cs_path=/opt/local/bin:/usr/bin:/bin:/usr/sbin:/sbin

but I don't know if that is such a good idea.

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slhck
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